C Programme to find the roots of an equation ax2 + bx + c = 0

program to find the roots of an equation ax² + bx + c = 0.


#include<stdio.h>

#include<conio.h>

#include<math.h>

int main()

{

            float a,b,c,alf,bt,dlt;

            clrscr();

            printf("\n Enter a: ");

            scanf("%f",&a);

            printf("\n Enter b: ");

            scanf("%f",&b);

            printf("\n Enter c: ");

            scanf("%f",&c);

            dlt=b*b-4*a*c;

            if(dlt==0)

            {

                        printf("\n ALPHA=BETA=%f",-b/(2*a));

            }

            else if(dlt<0)

            {

                        printf("\n Imaginary Roots");

            }

            else

            {

                        alf=(-b+sqrt(dlt))/(2*a);

                        bt=(-b-sqrt(dlt))/(2*a);

                        printf("\n\n Alpha = %f\n Beta=%f\n",alf,bt);

            }

            getch();

            return 0;

}

Output:

(1)

Enter a: 12

Enter b: 2

Enter c: 34

Imaginary Roots

(2)

Enter a: 2

Enter b: 6

Enter c: 2

Alpha = -0.381966

Beta = -2.618034

(3)

Enter a: 2

Enter b: 4

Enter c: 2

Alpha=Beta= -1.000000