programme to find a LCM and GCD of two numbers.
#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int
x,y,gcd=1;
cout<< "ENTER 1st NO : ";
cin>>x;
cout<<"\n\nEnter
2nd NO. :";
cin>>y;
for(int
i=1;i<1000;++i)
{
if((x%i==0)&&(y%i==0))
gcd=i;
}
cout<<"\n\n\nGCD
:"<<gcd;
cout<<"\n\n\nLCM
:"<<(x*y)/gcd;
getch();
}
OUTPUT:
ENTER 1st NO : 12
ENTER 2nd NO. :13
GCD :1
LCM :156
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